create table dlee(
username varchar2(32),
table_name varchar2(32)
);
/
insert into dlee
values('Anjan','Yamaha');
insert into dlee
values('Anjan','Bike');
insert into dlee
values('Anjan','R15');
insert into dlee
values('Anjan','Gwarko');
insert into dlee
values('Anjan','Dream');
insert into dlee
values('Anjan','CAR');
insert into dlee
values('Dilli','Suzuki');
insert into dlee
values('Dilli','Car');
insert into dlee
values('Dilli','Kirtipur');
select
username,
listagg (table_name, ',')
WITHIN GROUP
(ORDER BY username) username
FROM
dlee
GROUP BY
username
/
column table_list format a50
select
username, ceil(line/3) as Sequence,
listagg (table_name, ',')
WITHIN GROUP
(ORDER BY username) as table_list
FROM
(select
username, table_name, rank() over (partition by username order by table_name) as LINE from dlee)
GROUP BY
username,ceil(line/3)
/
username varchar2(32),
table_name varchar2(32)
);
/
insert into dlee
values('Anjan','Yamaha');
insert into dlee
values('Anjan','Bike');
insert into dlee
values('Anjan','R15');
insert into dlee
values('Anjan','Gwarko');
insert into dlee
values('Anjan','Dream');
insert into dlee
values('Anjan','CAR');
insert into dlee
values('Dilli','Suzuki');
insert into dlee
values('Dilli','Car');
insert into dlee
values('Dilli','Kirtipur');
Figure 1. Output of table dlee
select
username,
listagg (table_name, ',')
WITHIN GROUP
(ORDER BY username) username
FROM
dlee
GROUP BY
username
/
Figure 2. Output of listagg output
column table_list format a50
select
username, ceil(line/3) as Sequence,
listagg (table_name, ',')
WITHIN GROUP
(ORDER BY username) as table_list
FROM
(select
username, table_name, rank() over (partition by username order by table_name) as LINE from dlee)
GROUP BY
username,ceil(line/3)
/
Figure 3. Output of listagg output with 3 list in single line.
do you have dump question for sqlfoundation (1z0-051)exam
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